Answer / sumit jha

when ws peter as as paul is nw?? (x-y) years ago!!

so those years ago paul's age= y-(x-y) yrs

now qstn says peter is twice the age as paul ws then.

so x/2 = y-(x-y)

or x/2=2y-x

or x= 4y - 2x

or 3x = 4y

or y = 3/4x

rplacing d value of y in d equation x+y=35 we get answer as

-----
x=20
-----
y =15.
------

thus (x-y)=5 yrs ago y was 10 and x is twice that=20.
but x+y=35

Answer / paul

The answer is 21 years old (age of Peter).

Equation:

let x = present age of Peter
y = present age of Paul

When Peter has the same age as Paul (y yrs. old), age of
Paul is y/2 yrs. old. Since the differences of there ages
are equal for the 2 events, we have the equation...

x - y = y - y/2
y = (2/3)x

Substituting the equation of y to the equation x + y = 35,
will give us....

x + (2/3)x = 35

therefore, x = 21 (age of Peter)

Answer / guest

7yreas 6 months

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