Answer / dhruv sharma rkdf

#include<stdio.h>
#include<conio.h>
void main(){
int i,j;
clrscr();
for(i=1;i<=5;i++){
for(j=i;j<=5;j++){
printf("%d ",j)
}
printf("\n");
}
getch();
}

Answer / ep

#include <stdio.h>

int main()
{

for ( int i = 1; i <= 5 ; i++ ) {
for ( int j = i; j <= 5 ; j++ ) {
if ( i != j ) printf (" ");
printf( "%d", j );
};
printf("\n");
}

return 0;
}

Answer / jayaraj.s

#include <stdio.h>
main()
{
int a,b,i=1;
for(a=i;a<=5;a++)
{
for(b=a;b<=5;b++)
{
printf("%d",b);
}
printf("\n");
i++;
}
getch();
}

Answer / dhruv sharma rkdf

hello Jayaraj.s..........
your program will give the following compilation error:
"getch should have a prototype"

you need to include "conio.h" header file...

Answer / atul shukla

#include<stdio.h>
void main()
{
int i,j;
for (i=1;i<=5;i++)
{
for(j=i;j<=5;j++)
printf("%d ",j);
printf("\n");
}
}

Answer / letskools

I think th correct program is this for the above output
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
clrscr();

for(i=0;i<=5;i++)
{
for(j=i;j<=5;j++)
{
printf("%d",j);
}
printf("\n");
}
getch();
}

Answer / rajarshi bhadra

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
clrscr();

for(i=5;i>=0;i--)
{
for(j=1;j<=i;j++)
{
printf("%d",j);
}
printf("\n");
}
getch();
}

Answer / subasaranya

1 2 3 4 5
2 3 4 5
3 4 5
4 5
5

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