Answer / maddy

/*the snippet for the problem is consider arr[10][10],read
the co-ordinates from the user col[10],row[10]*/
for(i=0;i<n;i++)//where n is co-ordinte
{
for(j=0;j<n;j++)
{
row[i]+=arr[i][j];//getting each element in the row
col[i]+=arr[j][i];//getting each element in column
}
}

Answer / sreejesh1987

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,a[3][3],rowsum[3],colsum[3];
clrscr();

for(i=0;i<3;i++)
rowsum[i]=colsum[i]=0;

printf("Enter numbers in a 3x3 matrix:\n");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
{
scanf("%d",&a[i][j]);
rowsum[i]+=a[i][j];
colsum[j]+=a[i][j];
}


for(i=0;i<3;i++)
printf("RowSum[%d]:%d\n",i,rowsum[i]);

for(i=0;i<3;i++)
printf("Columnsum[%d]:%d\n",i,colsum[i]);

getch();
}

Answer / rana from hriyana

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,a[3][3],rowsum[3],colsum[3];
clrscr();

for(i=0;i<3;i++)
rowsum[i]=colsum[i]=0;

printf("Enter numbers in a 3x3 matrix:\n");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
{
scanf("%d",&a[i][j]);
rowsum[i]+=a[i][j];
colsum[j]+=a[i][j];
}


for(i=0;i<3;i++)
printf("RowSum[%d]:%d\n",i,rowsum[i]);

for(i=0;i<3;i++)
printf("Columnsum[%d]:%d\n",i,colsum[i]);

getch();
}

Answer / janel

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
int ar[3][3];
int a,b,R1,R2,R3,C1,C2,C3;

cout<<"Please Enter 9 numbers:"<<endl;
for (a=0;a<3;a++){
for (b=0;b<3;b++){

cout<<"["<<a<<"]["<<b<<"]:";
cin>>ar[a][b];
}
}
cout<<"The sum of the first row is: ";
R1=ar[0][0]+ar[0][1]+ar[0][2];
cout<<R1;
cout<<"\nThe sum of the second row is: ";
R2=ar[1][0]+ar[1][1]+ar[1][2];
cout<<R2;
cout<<"\nThe sum of the third row is: ";
R3=ar[2][0]+ar[2][1]+ar[2][2];
cout<<R3;

cout<<"\nThe sum of the first column is: ";
C1=ar[0][0]+ar[1][0]+ar[2][0];
cout<<C1;
cout<<"\nThe sum of the second column is: ";
C2=ar[0][1]+ar[1][1]+ar[2][1];
cout<<C2;
cout<<"\nThe sum of the third column is: ";
C3=ar[0][2]+ar[1][2]+ar[2][2];
cout<<C3<<endl;
getch();
system("pause");
}

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