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Determine the distance between x-intercept and 2-intercept
of the plane where equation is 6x+8y-32=72.(pls give me the
answer with a clear solution)
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Answer / gaurav jha
your given eqn. is of line not plane .. if there is eqn like
6x+8y-3z=72,then the intercept will we (6/72,8/72,-3/72)
means (12,9,24)..points on x,y and z axis will be
(12,0,0),(0,9,0),(0,024) respectively.now we can easily find
out the distance between any two points..so in this case
dis. b/w x and y intercept will be 15 and x and z will be
26.somthing..similarly we can determine the distane from any
intercept to any plane...
| Is This Answer Correct ? | 19 Yes | 2 No |
Answer / ashok
Sqrt of ((d/a)^2+(d/c)^2)
d=72
a=6
b=8
c=-3
(d/a)^2=144
(d/c)^2=576
Squrt(144+576)
| Is This Answer Correct ? | 16 Yes | 2 No |
Answer / yuvanish yuvaraj
put y and z = 0 to get x intercept which is x = 72/6 = 12
similarly z = 72/3 = 24
Distance between them be d
d2 = 122 + 242
= 720
d = sqroot of 720
thats 26.83...
oly one option close 2 dis will b thr...
| Is This Answer Correct ? | 13 Yes | 1 No |
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