Answer / h0rryp0tter

Please have a look at the code below :

char str[1];
int i = 0;
void revstr(void);

int main(void)
{

revstr();
printf("%s\n",str);

return 0;
}

void revstr(void)
{
char c = getchar();

if (c!= EOF) {
revstr();
str[i++] = c;
}
str[i] = '\0';
}

Written using Bloodshed Dev C++.

I am trying to access and write on an char array which has
been defined with only one element in it. The above code
must give me Errors of some kind. But on the contrary, it
works.

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }

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