main() { int i=5; printf("%d%d%d%d",i++,i--,i); }

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main()
{
int i=5;
printf("%d%d%d%d",i++,i--,i);
}

Question Posted / cholan

10 Answers
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main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / vara

4 5 5 and garbagevalue

Is This Answer Correct ?

12 Yes

4 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / mani

4 5 5

Is This Answer Correct ?

1 Yes

0 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / sravan kumer

Answer is 455848 in 'Turbo C++'
because here gave 4 %d's but given variables to print are 3.
So here Turbo C++ will evaluate first 3 parameters given as
---> first i will be evaluated so i=5 because printf() evaluates from right to left.
---> then i-- is 5 because it is post decrement so 1st prints value and then increments i=4
---> then i++ is post increments so 1st prints i value i.e 4
and then it will be incremented to 5.
---> so it printf will print 455 but there is another %d ,printf will handle those with a garbage values i.e 848 here.
so answer is 455848.i.e 455 is common after that some garbage value will be printed.

Is This Answer Correct ?

1 Yes

0 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / ajay karanam

4554202496

Is This Answer Correct ?

3 Yes

5 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / pranu

655

Is This Answer Correct ?

2 Yes

4 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / vignesh1988i

some garbage value , 4,5,5...

why in this o/p garbage value is because only 3 parameters
are passed but we have assigned 4 control strings , where
one control string is useless, so for that compiler will
print garbage value....

Is This Answer Correct ?

2 Yes

4 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / rukmanee

i++=5
i--=5
i=5

Is This Answer Correct ?

1 Yes

3 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / sravankumar

printf() function evaluates from right to left

printf("\n %d %d %d",i++,i--,i);
4 5 5
<- <- <- <- <-evaluation of expression
but prints as the way we mentioned in printf() function
i.e first i = 5
then i--= 5 because it is post decrement
then i++= 4 this because i is decremented in above, and
not incremented immediately because is post
increment
So output is : 4 5 5

Is This Answer Correct ?

0 Yes

3 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / sunil5a2

4 5 5

printf excutes form lefthand side onwords..

Is This Answer Correct ?

0 Yes

5 No

main() { int i=5; printf("%d%d%d%d",i++,i--,i); }..

Answer / cholan

55545

Is This Answer Correct ?

0 Yes

10 No

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