Answer / guest

Answer: A

Answer / subramani

A.in this two bits are borrowed
therefore no of networks is 4,no of hosts 64-2=62
Correct
B.in this three bits are borowed
therefore no of networks is 8,no of hosts 32-2=30
wrong
C.in this four bits are borrowed
therefore no of networks is 16,no of hosts 16-2=14
wrong
D.in this five bits are borrowed
therefore no of networks is 32,no of hosts 8-2=6
wrong

Answer / m haja bahurudeen

Ans :A

Class C - SNM : 255.255.255.0

Maxi 35 hosts SNM : 255.255.255.192

Total subnet : 4
Usable subnet : 2
Total hosts : 64
Usable hosts : 62
No of bits borrowed : 2

Answer / jitendera kumar sinha

ok we need 35 host and we have a class c address
now
2^n-2>=35
n=required bit for host
thus
n=6
that is we need six bit for host forn geting 35 hest per n/w
now how many spare bit we have
that is 8-6=2
thus take it for the n/w
then what is the mask of that sunated
i.e
128 64 32 16 8 4 2 1
1 1 0 0 0 0 0 0
that is mask of the last octect is 128+64=192
scince it is a class c address
thus complete mask shoud be
255.255.255.192
hence answer is a
no need to option byse calulation some above caluted it
option bise a wrong approch that was
jitendera kuamr sinha

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