suppose we have an interface & that interface contains five
methods. if a class implements that interface then we have
to bound that to give tha definition of all five methods in
that class. If we declare that class as abstract then can
we call only two methods to give the deinition of that
method & i don't want to give the definition of all the
methods? can it possible
Answers were Sorted based on User's Feedback
Answer / nitin
yes it is possible, just make rest of the method abstract
explictly.
Example:
public interface Human {
public void canEat();
public void canThink();
public void canTalk();
public void canImegine();
public void canLove();
}
public abstract class Man implements Human {
public abstract void canEat();
public abstract void canImegine();
@Override
public abstract void canLove();
@Override
public void canTalk() {
}
@Override
public void canThink() {
}
}
public class Nitin extends Man{
/**
* @param args
*/
public static void main(String[] args) {
}
@Override
public void canEat() {
}
@Override
public void canImegine() {
}
@Override
public void canLove() {
}
}
| Is This Answer Correct ? | 29 Yes | 1 No |
Answer / suresh chand
yes,it is possible that abstract class implements zero,
one,two,three or four interface methods but not all i.e
five. After this concrete class which extends the abstract
class, implements the remaining methods.
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / sai hegde
It's possible that your abstract class implements one/all or
none of the interface methods. The concrete class that
extends your abstract class will have to provide
implementations for the methods that have not been
implemented in your abstract class.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / srini
i think we can accomplish by using adapter design pattern.
| Is This Answer Correct ? | 0 Yes | 1 No |
yes it is possible, just make rest of the method abstract
explicitly.
public interface InterfaceSample {
public void method1();
public void method2();
public void method3();
public void method4();
}
abstract class Abstclass implements InterfaceSample{
public abstract void method1();
public abstract void method2();
public void method3(){
System.out.println(" astract method3 ..............");
}
}
public class Sample extends Abstclass {
public void method1(){
System.out.println("method1 ..............");
}
public void method2(){
System.out.println("method2 ..............");
}
public void method4(){
System.out.println("method4 ..............");
}
public static void main(String[] args) {
Sample s1 = new Sample();
s1.method1();
s1.method2();
s1.method3();
s1.method4();
}
}
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / pavan chaturvedi
no we have to override all methods of interface
| Is This Answer Correct ? | 2 Yes | 20 No |
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