suppose we have an interface & that interface contains five
methods. if a class implements that interface then we have
to bound that to give tha definition of all five methods in
that class. If we declare that class as abstract then can
we call only two methods to give the deinition of that
method & i don't want to give the definition of all the
methods? can it possible
- 6 Answers
- 8209 Views
- HP, Wipro, I also Faced
- E-Mail Answers
Answer Posted / nitin
yes it is possible, just make rest of the method abstract
explictly.
Example:
public interface Human {
public void canEat();
public void canThink();
public void canTalk();
public void canImegine();
public void canLove();
}
public abstract class Man implements Human {
public abstract void canEat();
public abstract void canImegine();
@Override
public abstract void canLove();
@Override
public void canTalk() {
}
@Override
public void canThink() {
}
}
public class Nitin extends Man{
/**
* @param args
*/
public static void main(String[] args) {
}
@Override
public void canEat() {
}
@Override
public void canImegine() {
}
@Override
public void canLove() {
}
}
| Is This Answer Correct ? | 29 Yes | 1 No |
Post New Answer View All Answers
How a string is stored in memory?
Java.util.regex consists of which classes?
Can size_t be negative?
What does += mean in java?
What restrictions are placed on method overriding?
What is lambda expression in java?
What is locale?
What is the static field modifier?
Is there any difference between synchronized methods and synchronized statements?
What is the difference between preemptive scheduling and time slicing?
What is tcp and udp?
How does predicate work in java?
What is a “stateless” protocol ?
Why spring singleton is not thread safe?
What are advantages of exception handling in java?
