program to check if a number is "perfect number".
Answer / athresh
public boolean isPerfect(int number)
{
int i = sumFactors(number);
if (i == number)
{
return true;
}
else
return false;
}
public int sumFactors(int number)
{
int factor = 0, sum = 0;
for (int i = 1; i < number; i++){
if (!(number % i)){
factor = i;
sum += factor;
}
}
return sum;
}
| Is This Answer Correct ? | 13 Yes | 13 No |
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