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Here's the programm code:
int magic(int a, int b) {
return b == 0 ? a : magic(b, a % b);
}
int main() {
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", magic(a, b));
return 0;
}
on input stream we have integers 4, 45
What's the output integer?
How many times will be initiated "magic" function?
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U hv to enter a range from a and b and search hw many no. of times a pattern n. occurs between the range a and b. Eg :i/p:enter range :0 100 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 0 to 100:1 Eg :i/p:enter range :100 1000 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 100 to 1000: (in this 13,113,131,132,133…139,213,313,…913 all these will be counted)
What output does this program generate as shown? Why? class A { A() { cout << "A::A()" << endl; } ~A() { cout << "A::~A()" << endl; throw "A::exception"; } }; class B { B() { cout << "B::B()" << endl; throw "B::exception"; } ~B() { cout << "B::~B()"; } }; int main(int, char**) { try { cout << "Entering try...catch block" << endl; A objectA; B objectB; cout << "Exiting try...catch block" << endl; } catch (char* ex) { cout << ex << endl; } return 0; }
swap prog
output for printf("printf");
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