Answer / ashutosh shashi

for(i=0;i<n-1;i++)
{
for(j=0;j<n-i-1;j++)
{
if(arr[j] >a[j+1])
{
temp=arr[j];
arr[j]=arr[j+1];
arr[j+1]=temp;
}
}
}

Answer / rama krishna sidhartha

//code for ascending order
for(i=0;i<n-1;i++)
{
for(j=1+1;j<n;j++)
{
if(a[j] >a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}

//code for descending order
for(i=n-1;i>0;i--)
{
for(j=n;j>i+1;j--)
{
if(a[j]<a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}

Answer / anon

#include <stdio.h>

int main() {
int i, j, size, values[100], temp;

printf("Enter the size of an array: ");
scanf("%d",&size);
printf("Enter the values of array: ");
for(i=0;i<size;i++){
scanf("%d",&values[i]);
}

for(i=0;i<size-1;i++){
for(j=i+1;j<size;j++){
if(values[i]<values[j]){
temp=values[i];
values[i]=values[j];
values[j]=temp;
}
}
}
printf("Sorted array:
");
for(i=0;i<size;i++){
printf("%d ",values[i]);
}

return 0;
}

Answer / guest

refer any good sorting tecnique

main() { enum _tag{ left=10, right, front=100, back}; printf("%d, %d, %d, %d", left, right, front, back); }

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write a program that accepts 3 numbers from the user. dispaly the values in a descending order.

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