Answer / vadivelt

1.Get i/p of 101 elements and add all the nos.And say the
result of that Addition is 'sum'.

2.We all know that n(n+1)/2 is formula to calculate the
addition of 'n' numbers.

if n = 100 then n(n+1)/2 give addtion of 1....100.
so say total = n(n+1)/2;

3.Now 'sum' holds the addition of 1....101 nos
And 'total' holds the addition of 1....100 nos

So the repeated no would be.,
Result = sum - total;

Equalent Code is.,

#include<stdio.h>
main()
{
int i, n, sum = 0, a[150], Total;
printf("ENTER SIZE OF ARRAY:\n");
scanf("%d", &n);
printf("\nENTER ELEMENTS OF ARRAY:\n");
for(i = 0; i<n; i++)
{
scanf("%d", &a[i]);
sum = sum + a[i];
}
n = n-1;
Total = (n *(n+1) /2);
printf("\nREPEATED NO: %d",sum - Total);
getch();
}

Answer / rahul

Binary Tree. But their exists better solution

Can you declare an array without a size in c++?

0 Answers  

---

What operator is used to access a struct through a pointer a) >> b) -> c) *

0 Answers  

---

What is size of a object of following class? class Foo { public: void foo(){} }

2 Answers   CA,

---

Can we use struct in c++?

0 Answers  

---

What is istream and ostream in c++?

0 Answers  

---

How many types of scopes are there in c++?

0 Answers  

---

Where is atoi defined?

0 Answers  

---

Why is the function main() special?

0 Answers  

---

Define the process of handling in case of destructor failure?

0 Answers  

---

Explain operator overloading.

0 Answers  

---

the maximum length of a character constant can be a) 2 b) 1 c) 8

0 Answers  

---

What is the iunknown interface?

0 Answers  

---