implement NAND gate logic in C code without using any
bitwise operatior.
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Answer / laxmi bose
#include<stdio.h>
main()
{
int a,b;
scanf("%d%d",&a,&b);
if(a==0||b==0)
{
printf("1");
}
else
{
printf("0");
}
| Is This Answer Correct ? | 42 Yes | 13 No |
Answer / senthil.cp
NAND using Bitwise operators
c = ~(a & b) OR
c = ~a | ~b
NAND without using bitwise operators
c = (0xFF - a) + (0xFF - b)
| Is This Answer Correct ? | 35 Yes | 16 No |
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