Answer / rajujadhav22

It is possible with ternary oprator.

Answer / sanjeet kumar

with the help of ternary operator

Answer / prady

#include<stdio.h>
#include<conio.h>


void main()
{


int a,b,c,temp,Num1,Num2;

printf("Enter 3 no\n");
scanf("%d%d%d",&a,&b,&c);
Num1=a;
Num2=b;
temp=Num1-Num2;
temp&=0x80000000;
temp>>=31;
switch(temp)
{
case -1: Num1=a;
Num2=c;
break;
case 0: Num1=b;
Num2=c;
break;

}
temp=Num1-Num2;
temp>>=31;
switch(temp)
{
case -1: printf("Smallest No is %d\n",Num1);
break;
case 0: printf("Smallest No is %d\n",Num2);
break;

}
getch();

}

Answer / ashutosh tiwari

if((a-b)&0x8000)
if((a-c)&0x8000)
printf("a is smaller");
else if((a-c)&0x7fff)
printf("c is smaller");
else
printf("a & c are equal & smaller");
else if((a-b)&0x7fff)
if((b-c)&0x8000)
printf("b is smaller");
else if((b-c)&0x7fff)
printf("c is smaller");
else
printf("b & c are equal & smaller");
else
if((b-c)&0x8000)
printf("b is smaller");
else if((b-c)&0x7fff)
printf("c is smaller");
else
printf("a, b & c are equal & smaller");

main() { char ch='356'; Printf("%d",ch); } *OUTPUT*:- -18 *Why?*

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