Answer / roshanpr

Functions that are expanded inline ( that we during there
call) is called inline functions.

Usually when there there is a function call the control is
taken to the function definition where the code is executed
and then the control returns back to main. But in case of
inline function there is no jump in the flow, rather the
function it self is expanded at the place of call.

You can make function inline in two ways.

1) Prefixing keyword "inline" durin the function
declaration.
2) By defining the function inside the class declaration

Ex: shows both the implementation

Class myClass
{

int age;

public:
inline void getAge();
void showAge()
{
cout<<"Age:"<<age;
}
};

void myClass getAge()
{
cout<<"Age:"<<age;
}

Answer / laxman

Inline function :-

In genereal function call branching method is there . In
inline function substitution takes place . Inline
functions are expanded during compilation . Exectution
becomes fast and branching is eliminated. Inline word is a
request but not command. If inline is not possible compiler
takes it like a genral function call.
rules:
1 function should be small
2. Controll statements are not valid like for ,while


if u need more mail to me

Answer / nashiinformaticssolutions

Functions expanded at the point of call, avoiding function call overhead.

What are dynamic type checking?

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write a program to add two numbers without using an arithmetic operator.

1 Answers   NIIT,

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class HasStatic { static int I; }; Referring to the sample code above, what is the appropriate method of defining the member variable "I", and assigning it the value 10, outside of the class declaration? a) HasStatic I = 10; b) int static I = 10; c) static I(10); d) static I = 10; e) int HasStatic::I = 10;

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What is exception handling in C++?

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How would you find out if a linked-list is a cycle or not?

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Is c++ map a hash table?

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