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Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x
is an integer
0 17 23 19

Answers were Sorted based on User's Feedback

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

Considering x=1

|-5-(-1)|+|2-(-1)|+|6-(-1)|+|10-(-1)|

4+1+5+9

19

 Is This Answer Correct ? 56 Yes 41 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

we can get 23-2x from eq.
if x=1.....value is 21
if x=2.....value is 19
if x=3.....value is 17
if x=4.....value is 15
so ans is.................17 for x=3 as per given options

 Is This Answer Correct ? 38 Yes 31 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

when x=2,
=|-5-(2)| + |2-(2)|+|6-(2)|+10-(2)|
=|-7|+|0|+|4|+|8|
=7+0+4+8
=19

 Is This Answer Correct ? 9 Yes 2 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

for x=2,3,4,5
f(x)=19.
so ans= 19

 Is This Answer Correct ? 6 Yes 1 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

 Is This Answer Correct ? 6 Yes 1 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

17

 Is This Answer Correct ? 41 Yes 38 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

if it is an modulus and not brackets then the minimum value is 23 with x=0

 Is This Answer Correct ? 25 Yes 23 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

5+x+2-x+6-x+10-x
=23-2x
so x=17

 Is This Answer Correct ? 11 Yes 9 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

Q: |-5-x| + |2-x|+|6-x|+10-x|
A:
firstly considering A.|2-x|+|6-x|+|10-x|, 6 is avg. of 2 & 10. So choosing x=6 will give min. value for these.
And then considering B.|-5-x|, This will be 5+x.
Finally putting the value of x in A&B and then adding it will give 19.

 Is This Answer Correct ? 0 Yes 0 No

Find min value of fn: |-5-x| + |2-x|+|6-x|+10-x|; where x is an integer 0 17 23 19 ..

Since x is an integer it can also be a negative number;
if x = -5
then fn = 9 which is the min. value for the fn.

 Is This Answer Correct ? 0 Yes 1 No

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