BE*BE =ACB
a,b,c and e are non zero value,find the result?

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BE*BE =ACB a,b,c and e are non zero value,find the result?..

Answer / vikram rathi

19*19=361
trick: B is the key element. since BE^2 is a 3 digit no., it cant be more than 31. hence possible values for B= 1,2,3.
now, unit digit of square is again B, which cant be possible with 2 or 3. only possibility is 1. B=1
now, E can be either 9 or 1. if E=1, then B=E=A=1, which doesnt make sense.
hence, E=9.

Is This Answer Correct ?    16 Yes 1 No

BE*BE =ACB a,b,c and e are non zero value,find the result?..

Answer / john smith

a,b,c,e=1,1,2,1

Is This Answer Correct ?    11 Yes 1 No

BE*BE =ACB a,b,c and e are non zero value,find the result?..

Answer / helenmary

11*11=121

19*19=361

Is This Answer Correct ?    5 Yes 1 No

BE*BE =ACB a,b,c and e are non zero value,find the result?..

Answer / yamuna

If the alphabet has unique value then the ans is
e=9 ,b=1,a=3,c=6
19*19=361

Is This Answer Correct ?    1 Yes 1 No

BE*BE =ACB a,b,c and e are non zero value,find the result?..

Answer / athipathy

21*21=441

29*29=841

Is This Answer Correct ?    4 Yes 6 No

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