source destination distance chennai bangalore 500 bangalore chennai 500 hyd delhi 1000 delhi hyd 1000 bangalore hyd 800 Here chennai to bangalore and bangalore to chennai is same distance. and hyd and delhi also same criteria. Based on the distance i want to display only one row using sql query?4 4275
While inserting/updating million of records into a database table, how do I came to know how many records has been inserted or updated successfully so far?
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There are 5 records in a table and we have implemented two triggers that are :pre_query and post_query how many times these triggers will fire.2 2078
table name: prod there are three fields in the table that are 1.proddate 2.prodQty 3.model Day wise prodQty is stored in the table prod write a query to display total prodqty in the year 2004 april.2 1534
table name :Tab fields name 1.trx_no (pk) 2.trx_date 3.account code (7 char) 4.account type (1 char) 5.amt Tab contains account code day wise debit and credit transaction , account type fiels can have 2 value D for debit and c for Credit . write a query to display the account code wise total debit and credit bal for the month of april 2004. write a query to display account code wise new amt credit for the april 20042 1795
Hi Guys, I have a situation where I need to access the column values from rowtype variable. However, the column names are dynamic. below is sample code: declare Cursor c1 is select * from emp; Cursor c2 is select column_name from xyztable; v_c2 c2%rowtype; v_str varchar2 v_value varchar2(200); begin for rec in c1 loop open c2;---this cursor has column names like EMPLOYEE_ID, FIRST_NAME, LAST_NAME etc. loop fetch c2 into v_c2; exit when c2%notfound; /* now lets say i want to access value of LAST_NAME from cursor c1, so I am writing below code, however it does not work as expected */ v_str:= 'rec.'|| v_c2.column_name; -- this will give me string like "rec.EMPLOYEE_ID" v_value:=v_str; end loop; end loop; end; / Plz help ASAP.Thanks.2 1435
create SQL (both DML/DDL) statements appropriate for the creation of relational structures & constraints and other objects for a given case study, the population of these tables and the manipulation (querying/updating) of the stored data. 2. Create, develop and use the PL / SQL Program Units Procedures, Functions as a progression towards Object Oriented Relational Database Programming. 3. Package a collection of logically related Procedures and Functions together to further move towards development of Objects which reflect the principle of Data Abstraction whereby only an Object specified in the Interface is accessible to the end user. 4. Select, create, and use appropriate Database Triggers to impose agreed specific constraints on a Database Table. 5. Provide a full and detailed evaluation which includes a comprehensive test execution plan and its implementation for each of the above. Consider the following case study: Perilous Printing is a medium size printing company that does work for book publishers throughout UK. The company currently has 10 offices, most of which operate autonomously, apart from salaries, which are paid by the head office. Currently the sharing and communication of data, is carried out using multi- user networked access to a centralised RDBMS. Perilous Printing jobs consist of printing books or part of books. A printing job requires the use of materials, such as paper and ink, which are assigned to a job via purchase orders. Each printing job may have several purchase orders assigned to it. Likewise, each purchase order may contain several purchase order items. The following tables form part of the transactional RDB that the company uses: office (office_no, o_addr, o_telno, o_faxno, mgr_nin) staff (staff_no, nin, fname, lname, s_addr, s_telno, gender, dob, position, taxcode, salary, office_no) publisher (pub_no, p_name, p_city, p_telno, p_faxno, credit_code, office_no) book_job (job_no, pub_no, job_date, job_desc, job_type, job_status, supervisor_nin) purchase_order (job_no, po_no, po_date) po_item (job_no, po_no, it_no, qty) item (it_no, it_desc, amt_in_stock, price) office contains details of each office and the office number (office_no) is the key. Each office has a Manager represented by the manager’s national insurance number (mgr_nin). staff contains details of staff; the staff_no is the key. The office that the member of staff works from is given by office_no. publisher contains details of publisher and the publisher number (pub_no) is the key. Publishers are registered with the nearest office in their country, given by office_no, and they are given a credit code that can have the values “AA”, “AB”, “BB”, “BC”, “CC”, “CD” and “DD”. If a publisher is to be deleted then not only the publisher’s entry from the publisher table will have to be removed but all the data associated with the particular supplier has to be deleted too book_job contains details of publishing jobs and the job number (job_no) is the key. The publisher is given by the publisher number (pub_no) and the supervisor for the job by supervisor_nin. The job type can be either null or urgent; whereas the job_status can be “ongoing” or “completed” purchase_order contains details of the purchase orders for each job and the combination of job number and a purchase order number (job_no, po_no) form the key. Each printing job may have several purchase orders assigned to it. item contains details of all materials that can be used in printing jobs and the item number (it_no) is the key. po_item contains details of the items on the purchase order and (job_no, po_no, it_no) forms the key. In the above given database schema, descriptions are strings of characters (at most 30 characters long), any dates (except the job_ date) stored cannot be after the current system date, and quantities and prices are assumed to be non-negative numbers.
What is the difference between database trigger and stored procedure?
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a table has 2 classifications 1)liabilities 2)earnings this liabitity has 2 elements with 2 input values and the earnings have 2 elements with 2 input values i wrote a query so that my input is liability savings amount1 amount2 xxxx null xxxxxx 0 xxx1 null xxxxx1 0 null yyyy 0 yyyy null yyy1 0 yyy1 my problem is --when i developed a report(d2k) with this data my o/p is liabilities,amount1,savings,amount2 xxxx xxxxxx xxx1 xxxxx1 yyyy yyyy yyy1 yyy1 how could i move this savings,savings values 2 palces up. can any body provide me witha better solution
How to Execute a Package in PL/SQL.?
Hi, I am new in oracle(SQL), could anyone help me in writing a correct SQL. Below is the table structure. Table: Subsc Fields: 1. Sub_no (this field will hold values of subscriber nos, for e.g. S111111, S222222, S333333, S444444, etc.) 2. s_status (this field will hold values for different status of subscriber, for e.g. 'A', 'S', 'C', etc.) 3. cus_id (this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) Table: Bill Fields: 1. Bill_no this field will hold values of bill nos for e.g. 11111111, 22222222, 33333333, 44444444, etc.) 2. b_status = (this field will hold values for different status of bill for e.g. 'O', 'C', 'S', etc.) Note: 1. The Sub_no is a Primary key of Subsc table. 2. The cus_id is a foreign in Subsc table (referred from Bill_no field of Bill table) 3. The Bill_no field is the Primary key of Bill table. Query A --> I wrote a query to select cus_id/Bill_no which is in status open (b_status = 'O') and having more than two active subscriber (i.e. S_status = 'A') in it ( i.e. more the two subscribers in same bill). select s.cus_id from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id having count(sub_no) = 2 Problem : The above query will give the cus_id (or rather bill_no) which are in open status (b_status ='O) and which are having TWO ACTIVE Subscribers (s_status ='A') in it. However, this query will also lists the cus_id/bill_no which are having more than TWO subscribers in it (but only two subscriber will be in Active status (s_status = 'A') and the others will be in s_status = 'C' or s_status = 'S'. Help needed: I want to write a query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it. B--> If I include the sub_no in the above query then NO row are returned. select s.cus_id, s.sub_no from subsc s where exists (select 1 from bill where bill_no = s.cus_id and b_status = 'O') and s_status = 'A' group by s.cus_id, s.sub_no having count(sub_no) = 2 Help needed: I want to modify the above query which will fetch ONLY the cus_id/bill_no which are in open status (b_status ='O') and which are having ONLY TWO ACTIVE subscribers (s_status ='A') in it ALONG with the sub_no. Thanks a lot in advance. Regards, Nitin
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