Method of findingthe dry ingredient quantity of 1 m3
concrete.
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Answer Posted / tarique08
suppose, concrete mix ratio = 1:1.5:3
then, sum = 1 1.5 3 = 5.5
as we know,dry material required for 1 cum. of concrete =
1.54 cum.
then we can find -:
(1) cement = 1*1.54/5.5 = .28 cum. or .28cum.* 28.8= 8.06
bags.
(2) sand = 1.5* 1.54/5.5 = .42 cum.
or .42cum.* 35.3 = 14.83 cubic feet.
(3) coarse aggregate = 3* 1.54/5.5 = .84 cum.
or .84 cum.* 35.3 = 29.65 cubic feet.
so, dry ingredient quantity required for 1 m3 of concrete-:
cement = 8.06 bags.
sand = 14.83 cft.
coarse aggregate = 29.65 cft.
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