Question { L&T, 188334 }

Method of findingthe dry ingredient quantity of 1 m3
concrete.

Answer

suppose, concrete mix ratio = 1:1.5:3
then, sum = 1 1.5 3 = 5.5

as we know,dry material required for 1 cum. of concrete =
1.54 cum.
then we can find -:

(1) cement = 1*1.54/5.5 = .28 cum. or .28cum.* 28.8= 8.06
bags.

(2) sand = 1.5* 1.54/5.5 = .42 cum.
or .42cum.* 35.3 = 14.83 cubic feet.

(3) coarse aggregate = 3* 1.54/5.5 = .84 cum.
or .84 cum.* 35.3 = 29.65 cubic feet.

so, dry ingredient quantity required for 1 m3 of concrete-:

cement = 8.06 bags.
sand = 14.83 cft.
coarse aggregate = 29.65 cft.

Question { L&T, 8067 }

how many bricks in 1 one cubic meter?

Answer

But in fields only 406 nos of bricks are required for 1 m3 of volume
Because of the volume of mortar nos of bricks are reduced to 406 from 500nos

Question { IEC, 6144 }

how many bricks are required for masonary trench having
length of 31 mtr, depth of 0.6 mtr and breadth of 0.45 mtr
on single brick work as well as double ( 9" ) brick work

Answer

Total volume is 8.37 m3
So 406 nos of bricks are required for 1m3
8.37×406=3399 nos of bricks are required