Answer Posted / abilask

Yes the said funtion add is overloaded.
But it is in ambiguous state because of passing element is
same.
Compiler will differ with the passing elements, but dont
consider the return value.
In this quiestion the two add funtion having two different
return type int & char * respectively.

I think the below one will be correct example for
overloaded function.

int add(int a,int b);

char *add(float a,int b);

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#include #include #include #include void select(char *items, int count); int main(void) { char s[255]; printf("Enter a string:"); gets(s); select(s, strlen(s)); printf("The sorted string is: %s.\n", s); getch(); return 0; } void select(char *items, int count) { register int a, b, c; int exchange; char t; for(a = 0; a < count-1; ++a) { exchange = 0; c = a; t = items[ a ]; for(b = a + 1; b < count; ++b) { if(items[ b ] < t) { c = b; t = items[ b ]; exchange = 1; } } if(exchange) { items[ c ] = items[ a ]; items[ a ] = t; } } } design an algorithm for Selection Sort

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