Answer Posted / swamy
Comp-3 fields occupy (n+1)/2 spaces , 1 being the sign
eg: Pic S9(7) COMP-3. Byte size = (7+1)/2 = 4
Pic S9(5)V99 COMP-3. Byte size = (5+2+1)/2 = 4
| Is This Answer Correct ? | 2 Yes | 0 No |
Post New Answer View All Answers
2 input fles: 2 flat files, with different number of records. both are having unique key for each record and already sorted in ascending order . match these files using unique key and in output only matching key value has to be written. please procide cobol logic
I need to compare 3 variables(dates) and do some processing based on the earliest date. There could be more then 1 date record in any of the 3 fields. What is the best way to code this?
Why do we code s9 (4) comp. Inspite of knowing comp-3 will occupy less space?
how to move the records from file to array table. give with code example
Write a program to explain size error.
Give some examples of command terminators?
If you are current on the owner of a set, what is the difference between obtain next and obtain first?
How do define dynamic array in cobol.
Discuss about changing dataset name in proc.
Why would you use find and get rather than to obtain?
how can i see junk values in dclgen or in hostvariable of comp ?
What are declaratives and what are their uses in cobol?
IF I mention stop run in CICS what happens?
I have to write to a outfile where the number of records in that file should be the header of that file using IMS.. can anyone help me in this issue
What is length is cobol?
