What is "far" and "near" pointers in "c"...?
Answers were Sorted based on User's Feedback
Answer / narasimha
"near" and "far" pointers are actually non-standard
qualifiers that you'll find only on x86 systems. They
reflect the odd segmentation architecture of Intel
processors. In short, a near pointer is an offset only,
which refers to an address in a known segment. A far pointer
is a compound value, containing both a segment number and an
offset into that segment.
Segmentation still exists on Intel processors, but it is not
used in any of the mainstream 32-bit operating systems
developed for them, so you'll generally only find the "near"
and "far" keywords in source code developed for Windows 3.x,
MS-DOS, Xenix/80286, etc.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / peter
I think it's kind of pointer for different computer
architecture such as X86, IBM power server and so on because
various model of memory model is different.
| Is This Answer Correct ? | 1 Yes | 7 No |
how to programme using switch statements and fuctions, a programme that will output two even numbers, two odd numbers and two prime numbers of the users chioce.
0 Answers Mbarara University of Science and Technology,
source code for delete data in array for c
#include<stdio.h> #include<conio.h> void main() { int a=(1,2,3,(1,2,3,4); switch(a) { printf("ans:"); case 1: printf("1");break; case 2: printf("2");break; case 3: printf("1");break; case 4: printf("4");break; printf("end"); } getch(); }
What is the subtle error in the following code segment? void fun(int n, int arr[]) { int *p=0; int i=0; while(i++<n) p = &arr[i]; *p = 0; }
posted by surbhi just now main() { float a = 5.375; char *p; int i; p=(char*)&a; for(i=0;i<=3;i++) printf("%02x",(unsigned char) p[i]); } how is the output of this program is :: 0000ac40 please let me know y this output has come
main() { int i; float *pf; pf = (float *)&i; *pf = 100.00; printf("\n %d", i); } a. Runtime error. b. 100 c. Some Integer not 100 d. None of the above
main() { int i; printf("%d",scanf("%d",&i)); // value 10 is given as input here }
String reverse with time complexity of n/2 with out using temporary variable.
main() { printf("\nab"); printf("\bsi"); printf("\rha"); }
char *someFun1() { char temp[ ] = “string"; return temp; } char *someFun2() { char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’}; return temp; } int main() { puts(someFun1()); puts(someFun2()); }
How to access command-line arguments?
#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }