Answer / susie

Answer :

Compiler error: Multiple declaration for error

Explanation

The name error is used in the two meanings. One means
that it is a enumerator constant with value 1. The another
use is that it is a type name (due to typedef) for enum
errorType. Given a situation the compiler cannot distinguish
the meaning of error to know in what sense the error is used:

error g1;

g1=error;

// which error it refers in each case?

When the compiler can distinguish between usages then
it will not issue error (in pure technical terms, names can
only be overloaded in different namespaces).

Note: the extra comma in the declaration,

enum errorType{warning, error, exception,}

is not an error. An extra comma is valid and is provided
just for programmer’s convenience.

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4 Answers  

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#include<stdio.h> #include<conio.h> void main() { int a=(1,2,3,(1,2,3,4); switch(a) { printf("ans:"); case 1: printf("1");break; case 2: printf("2");break; case 3: printf("1");break; case 4: printf("4");break; printf("end"); } getch(); }

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What is full form of PEPSI

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main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

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What is "far" and "near" pointers in "c"...?

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int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }

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plz send me all data structure related programs

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C program to print magic square of order n where n > 3 and n is odd

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main() { char c=' ',x,convert(z); getc(c); if((c>='a') && (c<='z')) x=convert(c); printf("%c",x); } convert(z) { return z-32; }

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Is the following code legal? struct a { int x; struct a *b; }

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main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

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You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

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