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In the village called TALAJA, only three TV channels are
available - Moon Plus, Mony and Mee TV.
Out of 4000 TV viewers in the village, 1500 watch Moon TV,
2000 watch Mony and 2500 watch Mee TV.
Amongst these, 500 viewers watch Moon Plus and Mony, 800
watch Moon Plus and Mee TV, and 1000 watch Mony and Mee TV.
How many viewers watch all three channels?
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Answer / guest
300 viewers watch all three channels.
Let's assume that total X viewers watch all three channels.
total viewers who watch only Moon Plus and Mony = 500-X
total viewers who watch only Moon Plus and Mee TV = 800-X
total viewers who watch only Mony and Mee TV = 1000-X
total viewers who watch only Moon Plus
= 1500 - (500-X) - (800-X) - X
= 200 + X
total viewers who watch only Mony
= 2000 - (500-X) - (1000-X) - X
= 500 + X
total viewers who watch only Mee TV
= 2500 - (1000-X) - (800-X) - X
= 700 + X
We know that total viewers are 4000. Summing up all 7 values,
X + (500 - X) + (800 - X) + (1000 - X) + (200 + X) + (500 +
X) + (700 + X) = 4000
X + 3700 = 4000
X = 300
Hence, total 300 viewers watch all three channels.
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / padma
I hav doubt.. if answer X is 300.
According to u, only moon viewers is 200+X=500 then total
number of moon viewers is (only moon)+(moon&
mony)+(moon&mee)+(all three)
i.e.,500+500+800+300=2100 which is not equal to 1500 as
given in data..
so mu answer is 0.
according to my calculation, (omly moon)=200,(moon&nomy)=500,
(moon&mee)=800, (all three)=0.
So totally 1500 which satisfies the given data.
Help me if iam wrong.
| Is This Answer Correct ? | 2 Yes | 0 No |
Wo kay chej hi jo saal may 1 baar aata hai months may 2 baar aata hai weeks may 4 baar aata hai or din may 6 baar
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