A train travels a certain distance taking 7 hrs in forward
journey, during the return journey increased speed 12km/hr
takes the times 5 hrs.What is the distance traveled
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Answer / harish
d=s*t
Forward Journey: d=s*7
Return Journey: d=(S+12)*7
s*7=(S+12)*7
s=30KM/Hr
d=30*7=210 KMS
The Distance is 210 KMS
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / amit
d=s*t
Forward Journey: d=s*7
Return Journey: d=(S+12)*5
s*7=(S+12)*5
s=30KM/Hr
d=30*7=210 KMS
The Distance of one side is 210 KMS
Total Distance is 420 kms.
| Is This Answer Correct ? | 0 Yes | 0 No |
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