Answer / immanuel

21 times

Answer / suma

21 is correct
suppose 1,2,3,4,5,6,7 people.
1st one(tillu) shakes hand with all other 6 members.
then 2nd one(bunty) with 5 people only,since already he
shook hand with tillu.
then 3rd one with 4 people only.(with tillu &bunty its
over)
so 6+5+4+3+2+1=21
(7th one need not do it. already every one shook hand with
him,so not counted him)

Answer / pradip

ok boys the answer is 21
let the friends be A,B,C,D,E,F,G
FIRSTLY, SECONDLY, THIRDLY, FOURTHLY, FIFTHLY, SIXTHLY,
A-B]1 B-C]7 C-D]12 D-E]16 E-F]19 F-G]21
A-C]2 B-D]8 C-E]13 D-F]17 E-G]20
A-D]3 B-E]9 C-F]14 D-G]18
A-E]4 B-F]10 C-G]15
A-F]5 B-G]11
A-G]6
===============21 TIMES
LASTLY,
G-HAS ALREADY DONE WITH EVERYBODY.......

Answer / frulog

Immanuel is correct ...
21 times

12
13
14
15
16
17
23
24
25
26
27
34
35
36
37
45
46
47
56
57
67

Answer / eric

correct answer is 21.
Srinivas is the foolest gye I have ever seen. Such fool
guys should not be allowed to post their bloody answers.

Answer / etty

21

Answer / anuj

E(n-1) ie sum of n-1
for n=2 E1=1
n=3 E2=2+1=3
n=4 3+2+1=6

so for n=7 no of hand shakes will be E6=6+5+4+3+2+1=21

Answer / sahas

7 people ... U need two people for one handshake.

Using nCr Combination formula = n! / { (n-r)!r! }

i.e, 7C2 = 7! / {(7-2)! 2!}

= 7*6*5*4*3*2*1 / {(5*4*3*2*1)*(2*1)}
= 7*6 /{(2*1)}
=21

Answer / raj

in he 7 peoples
1st person shakes remaing 6
2nd '' '' '' 5
3rd '' '' '' 4
4th '' '' '' 3
5th '' '' '' 2
6th '' '' '' 1
7th '' '' '' 0

total--------------------21

Answer / auswin

An alternate mathematical approach:
If 'n' people shake hand with each other, the first
person can shake hands with 'n-1' people, the second with
'n-2' people and so on till the last person with 'n-n i.e 0'
people.

So, the total number of handshakes are
n-1+n-2+n-3+....n-n which is nothing but n*n-(1+2+3+....n)
which is equal to
n^2 -(n(n+1)/2) = (2n^2-n^2-n)/2 = (n^2-n)/2 = n(n-1)/2 ..!!

Hence, the number of handshakes possible with n people is
n(n-1)/2......

7 people meet and shake hands with one another, how many handshakes occur?

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