print a semicolon using Cprogram without using a semicolon
any where in the C code in ur program!!
Answers were Sorted based on User's Feedback
Answer / bikash mazumdar
void main()
{
while(!printf("\nHello World"))
}
| Is This Answer Correct ? | 30 Yes | 36 No |
Answer / narasimha peruru
#include<stdio.h>
void main()
{
while( printf("%c", 59), 0)
{
}
}
| Is This Answer Correct ? | 1 Yes | 7 No |
Answer / anshu ranjan
#include<stdio.h>
void main()
{int a=59;
if(printf("%c",a)){}
}
\\the previous one was wrong
| Is This Answer Correct ? | 17 Yes | 32 No |
Answer / anshu ranjan
#include<stdio.h>
void main()
{char a=';';
if(printf("%c",a)){}
}
| Is This Answer Correct ? | 15 Yes | 49 No |
main() { char a[4]="HELL"; printf("%s",a); }
Is it possible to type a name in command line without ant quotes?
#include <stdio.h> #define a 10 main() { #define a 50 printf("%d",a); }
main() { float f=5,g=10; enum{i=10,j=20,k=50}; printf("%d\n",++k); printf("%f\n",f<<2); printf("%lf\n",f%g); printf("%lf\n",fmod(f,g)); }
main() { { unsigned int bit=256; printf("%d", bit); } { unsigned int bit=512; printf("%d", bit); } } a. 256, 256 b. 512, 512 c. 256, 512 d. Compile error
how to print 1 2 3 4 5 6 7 8 9 10 9 8 7 6 5 4 3 2 1 using any loop(for or while) only once(only 1 loop) and maximum 2 variables using C.
19 Answers Cap Gemini, Infosys,
#include<stdio.h> #include<conio.h> void main() { int a=(1,2,3,(1,2,3,4); switch(a) { printf("ans:"); case 1: printf("1");break; case 2: printf("2");break; case 3: printf("1");break; case 4: printf("4");break; printf("end"); } getch(); }
void main() { int k=ret(sizeof(float)); printf("\n here value is %d",++k); } int ret(int ret) { ret += 2.5; return(ret); }
which function is used to clear the buffer stream on gcc? for example: I wrote following code on gcc #include<stdio.h> int main(void) { char ch; int a,b; printf("\nenter two numbers:\t"); scanf("%d%d",&a,&b); printf("enter number is %d and %d",a,b); printf("\nentercharacter:\t"); scanf("%c",&ch); printf("enter character is %c",ch); return 0; } in above progarm ch could not be scan. why?plz tell me solution.
Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?
main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }
main() { char *p = “ayqm”; char c; c = ++*p++; printf(“%c”,c); }