write a non recursive shell script that accepts any number
of arguments and prints them in the reverse order
Answers were Sorted based on User's Feedback
Answer / naresh babu
echo "no of arguments:$#"
echo "arguments in reverse order:"
for i in $*
do
j=$i" "$j
done
echo $j
| Is This Answer Correct ? | 26 Yes | 9 No |
Answer / drths
$ sh rev.sh 123 ---Script name with 1 cmd line argument
------------------------------
#! /bin/sh
abc=$1 ###123 will store in abc
pqr=`echo $pqr | rev` ### 123|rev
echo $abc
-----------------------------
o/p : 321
| Is This Answer Correct ? | 0 Yes | 5 No |
Answer / amar
./reverse frg gh rtyh
no of arguments:3
arguments in reverse order:
rtyh gh frg
| Is This Answer Correct ? | 0 Yes | 8 No |
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RAM one table colums a1,a2,a3,a4 respective values 2,4,7,8 KRISH one table colums a1,a2,a3,a4 respective values 3,4,6,9 IN RAM & KRISH a4 column if comparing values RAM A4 - KRISH A4 ( 8-9 =1 THEN print 5 or (RAM) a4 value 10 KRISH a4 values 2 then 10 -2 =8 print 5*8=40 or diff 5 print same
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