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write a non recursive shell script that accepts any number
of arguments and prints them in the reverse order

Answers were Sorted based on User's Feedback



write a non recursive shell script that accepts any number of arguments and prints them in the rev..

Answer / naresh babu

echo "no of arguments:$#"
echo "arguments in reverse order:"
for i in $*
do
j=$i" "$j
done
echo $j

Is This Answer Correct ?    26 Yes 9 No

write a non recursive shell script that accepts any number of arguments and prints them in the rev..

Answer / drths

$ sh rev.sh 123 ---Script name with 1 cmd line argument
------------------------------
#! /bin/sh
abc=$1 ###123 will store in abc
pqr=`echo $pqr | rev` ### 123|rev
echo $abc
-----------------------------
o/p : 321

Is This Answer Correct ?    0 Yes 5 No

write a non recursive shell script that accepts any number of arguments and prints them in the rev..

Answer / amar

./reverse frg gh rtyh
no of arguments:3
arguments in reverse order:
rtyh gh frg

Is This Answer Correct ?    0 Yes 8 No

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