In a Class 52% students has passed in Mathematics, 40%
students has passed in Physics, 17% students has passed in
both the subjects. So, how many percentage of students
hasn't passed in both the subjects?
Answers were Sorted based on User's Feedback
Answer / ustad
Anan is most definitely correct. You must read the
question carefully (even though the grammar is off -
probably someone from India fresh off the boat). "So how
many percentage of students hasn't passed in both the
subjects". You can interpret this as "What percentage of
students did not pass math and did not pass physics i.e)
failed ENTIRELY
So:
52% of the students passed in math. This percentage *may*
include those that also passed physics. Since we would like
to isolate those students who passed in math exclusively, we
subtract this percentage by 17 which represents those who
passed in BOTH. This leaves us with 35% who exclusively
passed in MATH ONLY.
We perform a similar operation to the physics portion and
subtract 40% from 17% which is 23%. This means 23% who
exclusively passed in PHYSICS ONLY.
Now to find out the percentage of students who have not
passed in BOTH is easy:
(those who passed in math ONLY) + (those who passed in
physics ONLY) + (those who passed in both)
= 35 + 23 + 17 = 75
So 75% of the class passed in either math, physics or BOTH.
So what is the percentage of student who have not passed
both subjects (basically failed completely)?
=(total percentage) - (those who passed in either math,
physics or both)
= 100 - 75
= 25
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / vijay kumar
for example assume 100 students there in a class
1.52%students are passed in maths
2.40%students in physics
3.17%in both
so:as 17%students are already included in 52%and40%so the
reamining ans is 8%
Is This Answer Correct ? | 1 Yes | 1 No |
Answer / prema
for example assume 100 students.
1.52 student pass in maths.
2.40 students pass in phy.
3.17 students pass in maths and phy
So.52-17=45 students pass in maths only
40-17=23 students pass in phy only
45+23+17=85 students pass in atleast one subject..
Ans is 100-85=15% students hasn't passed in both the subjects
Is This Answer Correct ? | 2 Yes | 3 No |
Answer / aman
for example assume 100 students.
1.52 student pass in maths.
2.40 students pass in phy.
3.17 students pass in maths and phy
So.52-17=35 students pass in maths only
40-17=23 students pass in phy only
35+23+17=75 students pass in at least one subject..
Ans is 100-58=25% students hasn't passed in both the subjects
Is This Answer Correct ? | 0 Yes | 1 No |
Answer / ramesh
n(a)=58
n(b)=40
n(AnB)=17
n(AuB)=n(a)+n(b)-n(a-b)
52+40-17
9217
75%
Is This Answer Correct ? | 1 Yes | 3 No |
Answer / xxx
hey mathi...first of all, u nly failed in substraction ...hw can u find the failures of others....
Is This Answer Correct ? | 1 Yes | 4 No |
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