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a program using one dimensional array that searches a number
if it is found on the list of given input numbers given by
the user and locate its exact location in the list..
""EXAMPLE""
enter how many numbers to be inputted: 5
12 14 11 09 30
what number to search: 11
11 IS FOUND IN LOCATION 3

PLZZZ.. ELP ME...

Answers were Sorted based on User's Feedback



a program using one dimensional array that searches a number if it is found on the list of given i..

Answer / mukesh yadav

int i,j,a[5];
printf("enter the numbers");
for(i=1;i<=10;i++)
{
scanf("\n%d",a[i]);
}
printf("what number to search:");
scanf("%d",j);
for(i=1;i<=10,i++)
{
if(j==a[i])
{
printf("FOUND IN LOCATION:",i);
exit(0);
}
}

Is This Answer Correct ?    13 Yes 10 No

a program using one dimensional array that searches a number if it is found on the list of given i..

Answer / fabiha nazmi

#include <stdio.h>
#include <string.h>
int main()
{
int num[10], a,d, s, i;
printf("Enter how many numbers to be inputted: ");
scanf("%d", &d);

for (i=0; i<d; i++)
{
scanf("%d", &num[i]);
}
printf("what number to search: ");
scanf("%d", &s);
for(i=0; i<d; i++)
{
if (s==num[i])
{
printf("%d is found in location %d", s, i+1);
break;
}
else
{
printf("Not found");
break;
}
}

return 0;
}

Is This Answer Correct ?    4 Yes 4 No

a program using one dimensional array that searches a number if it is found on the list of given i..

Answer / fabiha nazmi

#include <stdio.h>
int main()
{
int num[10], a,d, s, i;
printf("Enter how many numbers to be inputted: ");
scanf("%d", &d);

for (i=0; i<d; i++)
{
scanf("%d", &num[i]);
}
printf("what number to search: ");
scanf("%d", &s);
for(i=0; i<d; i++)
{
if (s==num[i])
{
printf("%d is found in location %d", s, i+1);
break;
}
}
return 0;
}

Is This Answer Correct ?    2 Yes 2 No

Post New Answer

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