Answer / suresh

let, x be man travel from A to B and
Y be man travel from B to A then
Average speed is (2XY)/(X+Y)
therefore ans = (2*4*5)/(4+5)
= 4.44mph

Answer / david

Imagine that the distance from A to B is 20 miles (lowest
common denominator of 4 and 5)

That means on the way there it took him 5 hours (20/4)
On the way back it took him 4 hours (20/5)

So in total it took him 9 hours (5+4) to travel 40 miles (20
miles each way).

So 40/9 = 4.444mph

Answer / guest

avg speed =2xy/x+y

avg speed=2*4*5/(4+5)

=40/9=4.444mph

Answer / srini

4.444 mph

Answer / amrutha

2*4*5/4+5=40/9=4.44

Answer / kishore jangid

Average Speed:
(2xy)/(x+y)
Therefore
=(2*4*5)/(4+5)
=(40)/(9)
=4.4444...

Answer / raviraj mishra

FORMULA FOR AVG. SPEED WHEN DISTANCE TRAVELLED IN TWO
INTERVALS IS SAME , IS GIVEN BY = 2*A*B/A+B
, A=4mph & B=5MPH SO ANSWER=4.44mph

Answer / bala

man A to B = 4mph
man B to A = 5mph

(4/100=4%, 5/100=5%)

average speed =4mph+5mph/200*100
=4.5mph.

Answer / shriram

4.5 mph

Answer / guest

4.5

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