I'm having trouble with coming up with the correct code. Do
I need to put a loop? Please let me know if I'm on the right
track and what areas I need to correct. I still don't have a
good grasp on this programming stuff. Thanks =)
The assignment was to write a program using string functions
that accepts a coded value of an item and displays its
equivalent tag price. The base of the keys:
0 1 2 3 4 5 6 7 8 9
X C O M P U T E R S
Sample I/O Dialogue:
Enter coded value: TR.XX
Tag Price : 68.00
Answers were Sorted based on User's Feedback
#include<stdio.h>
#include<string.h>
void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
//clrscr();
printf("Enter coded value: ");
scanf("%s",ip);
// printf("\nur entered code = %s",ip);
printf("\nUr price is = ");
for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
}
//compiled by GCC
| Is This Answer Correct ? | 6 Yes | 4 No |
Answer / levixnu
#include<stdio.h>
#include<string.h>
#include<conio.h>
void main()
{
char
v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'},p='.';
int v2[11]={0,1,2,3,4,5,6,7,8,9};
char ip[10];
int n,i,j,k=0,cnt=0;
clrscr();
printf("Enter coded value: ");
scanf("%s",ip);
printf("\nur entered code = %s",ip);
printf("\nUr price is = ");
for(i=0;v1[i]!='\0';i++)
{
if(ip[k]=='.')
{
++k;
printf("%c",p);
}
if(ip[k]==v1[i])
{
printf("%d",i);
++k;
i=-1;
if(ip[k]=='\0')
break;
}
}
getch();
}
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / roxy
#include<stdio.h>
#include<string.h>
main()
{
char v1[11]={'X','C','O','M','P','U','T','E','R','S','\0'};
char v2[11]={'0','1','2','3','4','5','6','7','8','9','\0'};
int n;
clrscr();
printf("Enter coded value: ");
scanf("%s",v1);
n=strncpy(v1, v2, 1);
v2[1]='\0';
printf("\nTag Price: %s ",v2);
getch();
}
| Is This Answer Correct ? | 3 Yes | 14 No |
2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]
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