void main() { int i=5; printf("%d",i+++++i); }

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void main()
{
int i=5;
printf("%d",i+++++i);
}

Question Posted / taruna

14 Answers
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void main() { int i=5; printf("%d",i+++++i); }..

Answer / nagarajan

If it is i++ + ++i the output will be 12 because
i++ =6
++1 =6

6+6=12

but in this case continuous five plus will show error .

compiler cannot identify operands there must be a space in between

Is This Answer Correct ?

55 Yes

21 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / junaid

well if you write all 5+ without space then it will give an error because compiler will not recognize it
you can write i++ + ++i or ++i + i++
answer in both statements will be 12

Is This Answer Correct ?

16 Yes

7 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / m

oly error wil be produced

Is This Answer Correct ?

9 Yes

2 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / harshawardhan

all functions pass the value from right to left and printf()
is one function therefore
i++ + ++i
in this siquence first solve the ++i and then solve the i++
first incrment by one i.e. 6 and then it solve i++ i.e. 5

printf("%d",i++ + ++i);
printf("%d",i++ + 6);
printf("%d",6 + 6);
printf("%d",12);

And therefoe output is:-

12

Is This Answer Correct ?

13 Yes

9 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / sadfasd

hmmm

Is This Answer Correct ?

2 Yes

2 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / gaurav tyagi

first of all
i want to say every one plz write ans if you are fully confident otherwise run it
///in this program a error is occurs because compiler not recognize the code <i am run this one>

Is This Answer Correct ?

3 Yes

3 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / srinivas

printf allways it will work from right to left so first
++i=6 after that i++ also 6 so 6+6=12 ..

Is This Answer Correct ?

9 Yes

10 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / vns

Increment operator(++i) only increases i value. At first ++i, i value becomes 6. Then there's another ++i, now i value is 7. both increment operations are evaluated since it has higher precedence than addition. So (++i) +(++i)= (i)+(i)= 7+7=14.

compile and run the program and you will get 14.

Is This Answer Correct ?

1 Yes

2 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / rohit surutkar

error

Is This Answer Correct ?

2 Yes

4 No

void main() { int i=5; printf("%d",i+++++i); }..

Answer / taruna

plzzz explain this ...why can't its answer be 12..???
plzz give proper explaination....waitin!!!

Is This Answer Correct ?

4 Yes

7 No

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