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Every year on the day of Janmashtami, both Mr. Deepak Patel
and Mr. Radha Krishnan distribute sweets free of cost at
their respective shops. Last year on the day of Janmashtmi,
there were a total of 1013 and 1057 people standing in two
different queues in front of the shops of Mr. Deepak Patel
and Mr. Radha Krishnan respectively. If there are at least
3 women between any two men in each of these two queues,
then the total number of men in both the queues cannot be
more than
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Answer / pradeep bagri
the ans. is 519
as 3 women r b/w 2 men so it means at first place there is a
man and behind him are three women. so they form a group of 4.
1013%4=1 and 1012/4=253. so the remainder 1 is a man as
before him are 3 women.
so in first queue there are 254 men.
by the same way in second queue there are 265 men.
and the total men in first queue can't be more than 254
and the total men in second queue can't be more than 265
and total are 519
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / ifteqar ali
in first queue 1013 total
number of persons/total number of men and women in between
each other.
so, 1013/3+2=5
1013/5=202.6
202.6 X number of women in between men is 3
so 202.6 X 3= 607.8 means 608
202.6 X 2 = 405.2 means 402
apply same formula for second queue
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / payal
since there r 3 women between any two men..dat means after every 3rd woman there is a men i.e. men is at 4th place ...so
1013/4=253(approx)
1057/4=264(approx)
thus total men=517
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / raki
atleast 3 girls must be there because they want max no of
men so 5 members form a bunch,1010/5=202,and in each bunch 2
are boys so in 202 groups no of men are 202*2,same way 210*2
| Is This Answer Correct ? | 0 Yes | 0 No |
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