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if we create a file, in that 10 rows(means 1,2,....9,10
like). i want 7 row exactly, which command use in unix?
plz send this question.
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Answer / thomas k
please try this. it will work.
head -7 <filename> | tail -1
| Is This Answer Correct ? | 42 Yes | 8 No |
Answer / srinu gadipudi
Just try this command
awk 'NR==7{print}' fiename
| Is This Answer Correct ? | 20 Yes | 3 No |
Answer / kantha
Hi, If you want to display 7th line from the file, simple
way is,
$head -7 <filename>| tail -1
Thanks
Kantha
| Is This Answer Correct ? | 7 Yes | 0 No |
Answer / isha
Put the command in Present working dir
head -7 <filename>
| Is This Answer Correct ? | 16 Yes | 10 No |
Answer / deshdeep saxena
awk 'NR==7{print}' filename will give you the seventh line
as output
awk 'NR<=7[print]' filename will give you from 1st line to
the seventh line :-)
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / murthy
Hi,
Try with the below command
sed -n '7p' <file name>
| Is This Answer Correct ? | 1 Yes | 0 No |
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