WHAT WILL BE THE OUTPUT OF THE FOLLOWING QUESTION
void main()
{
int x=4,y=3,z;
z=x-- -y;
printf("%d%d%d",x,y,z);
}
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Answer / arunkumar
it will be 3,3,1
no doubt it is the correcct one..
if anybody have a doubt compile and execute it with turbo c.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / jasmeet singh
hey i typed the output of x=4 but its 3. coz after the
decrement now its value is 3.
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / ramya b.m
The output will be 3 3 1. initially the value of x is 4 and
subtracting it with value of y which is 3 the difference is
1. while printing the value of x is decremented by 1 and
hence the output 3 3 1.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / tommy tom
331
x = 4-- = 3
y = 3
z = 1
then, when printing, there are no spaces in the "%d%d%d" format string, thus there are no spaces in the printing of the numbers. Also, at the end of the run, the command prompt will be tacked onto the end of the output, as the format string contains no newlines, line returns, or other reasons to assume a nice printing.
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / guru1985
#include<stdio.h>
#include<conio.h>
void main()
{
int x=4,y=3,z;
z=x-- -y;
printf("x=%d\ny=%d\nz=%d",x,y,z);
}
Output=>
x=3
y=3
z=1
| Is This Answer Correct ? | 0 Yes | 3 No |
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