Answer / pavan_mustyala

/**********
First construct the structure with total count on numbers
to be added. Now these members are accessed via that
structure variables. In the below example, structure
contains 2 numbers only.
***********/
#include <stdio.h>

struct numbers
{
int num1;
int num2;
};

void main()
{
struct numbers mpk;
int result;

printf("Enter two numbers");
scanf("%d%d",&mpk.num1, &mpk.num2);

result = mpk.num1 + mpk.num2;
}

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

1 Answers  

---

Write a program to receive an integer and find it's octal equivalent. How can i do with using while loop.

2 Answers  

---

main() { static char names[5][20]={"pascal","ada","cobol","fortran","perl"}; int i; char *t; t=names[3]; names[3]=names[4]; names[4]=t; for (i=0;i<=4;i++) printf("%s",names[i]); }

2 Answers  

---

Derive expression for converting RGB color parameters to HSV values

1 Answers  

---

write a program in c language to get the value of arroy keys pressed and display the message which arrow key is pressed?

1 Answers  

---

---

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

---

main() { while (strcmp(“some”,”some\0”)) printf(“Strings are not equal\n”); }

1 Answers  

---

main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; } a. Runtime error. b. Runtime error. Access violation. c. Compile error. Illegal syntax d. None of the above

1 Answers   HCL,

---

char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  

---

1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.

3 Answers  

---

how can i search an element in an array

2 Answers   CTS, Microsoft, ViPrak,

---

main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }

1 Answers  

---