f(char *p)
{
p=(char *)malloc(sizeof(6));
strcpy(p,"HELLO");
}
main()
{
char *p="BYE";
f(p)
printf("%s",p);
}
what is the output?
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Answer Posted / smirnov_amm
It will show "HELL"
the f function reserve only 4 bytes with the sizeof(6). it will return the sizeof (int) =4 bytes.
So you only allocate 4 bytes.
When performing the strcpy, you will corupt memory because you'll copy more than allocate.
Cheers
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