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Answer Posted / dr.shaukat saeed khan
It is equivalent to Vmax being the number of substrate
molecules converted to product by one enzyme molecule in
unit time(often 1 second)when there is saturation of the
substrate. Mathematically it can be expressed as
Kcat=Vmax/Et,
where Kcat=Turn over number
Vmax=Maximum rate of reaction when all the active sites of
the enzyme are saturated with the specific substrate
Et=Total enzyme concentration or the concentration of
active sites of the enzyme.
The turn over number differs from enzyme to enzyme under
identical experimental conditions and under different
conditions for the same enzyme.
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