Answer Posted / shrikant

people...
listen
this is the case of optimisation....
if u take 4 balls set then u end up in 3 tries...
if u take 3 3 2 set...
then try and see
frst weight 3..3
u no the unbalanced one...
select that set and put any two random balls in both pans...
if equal the ball not put in is the ball of concern...
else we are left with the other set...
that can be done easily..
2 balls each in one pan...
thats it

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