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A man while going dowm in a escalator(which is miving down)
takes 50 steps to reach down and while going up takes 125
steps. If he goes 5 times faster upwards than downwards.
What will be the total no of steps if the escalator werent
moving.
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Answer Posted / sammy
eq 1 : 50 + s = d (while 50 steps covered escalator goes
down by s steps. total steps covered is d which is constant)
NOW,
50 steps of the p --- s steps of escalator
125 steps of person --- s*125/50 steps of escalator
but while going up speed was 5 times faster
there4,
125 steps of p--- (s*125)/(50*5) = s/2
eq 2 : 125 - s/2 = d
solving we get d = 100 (ans)
| Is This Answer Correct ? | 4 Yes | 3 No |
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