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if a number is choosen between 100 and 999 includeing these
numberrs what is the provbabilty that the number selected
does not contain a 7 is
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Answer Posted / sandhya
let take xyz as number that can qualify our condition...
x can have capable of arranging in 8 ways bcoz 0 and 7 are
omitted..
y can can have capable of arranging in 9 ways bcoz 7 is
omitted...
z also same as y.
so totally we can get 8*9*9 ways and total numbers exist in
b/w 100 and 999 is 899
so the answer is 8*9*9/899
| Is This Answer Correct ? | 3 Yes | 9 No |
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