sk arman


{ City } noida
< Country > india
* Profession * r & d engineer
User No # 99873
Total Questions Posted # 0
Total Answers Posted # 3

Total Answers Posted for My Questions # 0
Total Views for My Questions # 0

Users Marked my Answers as Correct # 6
Users Marked my Answers as Wrong # 2
Questions / { sk arman }
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Answers / { sk arman }

Question { NTPC, 5498 }

what are the problems are there
if power factor is leading


Answer

When the power factor is leading, the capacitive kVAr is
more than the Inductive kVAr and this still has to be
supplied by the source. As kVA is the vector sum of kW and
kVAr, still for the given kW, you have to produce more kVA.
Alternately, for the given kVA, you can only convert
partially into useful work.

Secondary effects are voltage boost in the system,
availability of stored energy to feed the fault in case of a
fault, increase in the asymmetrical component of fault
current, increasing thus the peak value of the fault
current, etc.

Is This Answer Correct ?    3 Yes 1 No

Question { NTPC, 5498 }

what are the problems are there
if power factor is leading


Answer

When the power factor is leading, the capacitive kVAr is
more than the Inductive kVAr and this still has to be
supplied by the source. As kVA is the vector sum of kW and
kVAr, still for the given kW, you have to produce more kVA.
Alternately, for the given kVA, you can only convert
partially into useful work.

Secondary effects are voltage boost in the system,
availability of stored energy to feed the fault in case of a
fault, increase in the asymmetrical component of fault
current, increasing thus the peak value of the fault
current, etc.

Is This Answer Correct ?    2 Yes 1 No


Question { NTPC, 5498 }

what are the problems are there
if power factor is leading


Answer

When the power factor is leading, the capacitive kVAr is
more than the Inductive kVAr and this still has to be
supplied by the source. As kVA is the vector sum of kW and
kVAr, still for the given kW, you have to produce more kVA.
Alternately, for the given kVA, you can only convert
partially into useful work.

Secondary effects are voltage boost in the system,
availability of stored energy to feed the fault in case of a
fault, increase in the asymmetrical component of fault
current, increasing thus the peak value of the fault
current, etc.

Is This Answer Correct ?    1 Yes 0 No