Question { L&T, 188087 }

Method of findingthe dry ingredient quantity of 1 m3
concrete.

Answer

volume of concrete considering 1m3

ration 1:2:4

1+2+4= 7
cement
1/7+40%(compaction)+5%(waste)
0.142+0.0572+0.00715=0.20735m3
density of cement = 1440kg/cm3
1m3 of cement = 1440kg/cm3
xm3 contains 50kg = 50/1440 = 0.035m3
no of bags of cement =0.20735/0.035= 5.92bags

Sand
2/7 + 40% + 5%
0286 + 0.1144 + 0.143=0.4147m3
3.33m3 of lorry = 5cubic yard
no of load = 0.414/3.33 =0.125load/m3
Granite
4/7 + 40 + 5
0.572 + 0.229 + 0.0286 = 0.8296m3
3.33m3 of lorry = 5cubic yard
no of load = 0.8296/3.33 =0.25load/m3

cements = 6bags

Sand = 0.125load/m3

Granite = 0.250load/m3

Question { Interscape, 134156 }

How to convert rainforcement calculation: Running meter to kg

Answer

16mm diameter bar


weigh factor for 16mm
16 x16 x 0.00617=1.579kg

whatever u get multipy by the weigh factor gives u the
kilogram of the reinforcement