Question { CTS, 65372 }

void main()
{
for(int i=0;i<5;i++);
printf("%d",i);
}

What is the output?..

Answer

the answer is...........0




because in c,c++ program when the semicolon is present then it is considered as one statement
here for loop has a semicolon so it consider one statement and execute only one so that the initial value o is printed

Question { HCL, 8330 }

void main()
{
int i=7;
printf("N= %*d",i,i);
}

Answer

N= 7




it doesnot consider the * symbol and the other i.

Question { Wipro, 5964 }

what is exceptions?

Answer

sometimes difficult stage to get the correct answer for any program in this case the exception is used to solve the case
eg:: divide by 0
overflow of array size

Question { TCS, 6394 }

What is the out put of this programme?
int a,b,c,d;

printf("Enter Number!\n");
scanf("%d",&a);
while(a=!0)

{
printf("Enter numbers/n");
scanf("%d%d%d",&b,&c,&d);
a=a*b*c*d;

}
printf("thanks!");

getche();

Entering numbers are
a=1,b=2,c=3,d=4
b=3,c=4,d=-5
b=3,c=4,d=0

Answer

Enter Number!
1
Enter numbers
2 3 4
Enter numbers
3 4 -5
Enter numbers
3 4 0
thanks!