CHEMICAL MATERIAL BALANCE - EXAMPLE 2.5 : In a non-dilute absorber, the inlet gas stream consists of 8 mol % carbon dioxide in nitrogen. By contact with room temperature water at atmospheric pressure, 65 % of the carbon dioxide from a gas stream has been removed. (a) Find the mole ratio of carbon dioxide and nitrogen gases at inlet and outlet gas streams. (b) The Henry's Law provides y = 1640 x for carbon dioxide in water. Find the mole ratio when x = 0.0000427. Mole ratio is y / (1 - y) for y.
1 2484Question 80 - Liquid octane has a density of 703 kilograms per cubic metre and molar mass of 114.23 grams per mole. Its specific heat capacity is 255.68 J / (mol K). (a) Find the energy in J needed to increase the temperature of 1 cubic metre of octane for 1 Kelvin. (b) At 20 degree Celsius, the solubility of liquid octane in water is 0.007 mg / L as stated in a handbook. For a mixture of 1 L of liquid octane and 1 L of water, prove by calculations that liquid octane is almost insoluble in water.
1 2964Question 82 - (a) The Hyperion sewage plant in Los Angeles burns 8 million cubic feet of natural gas per day to generate power in United States of America. If 1 metre = 3.28084 feet, then how many cubic metres of such gas is burnt per hour? (b) A reservoir of natural gas produces 50 mole % methane and 50 mole % ethane. At zero degree Celsius and one atmosphere, the density of methane gas is 0.716 g / L and the density of ethane gas is 1.3562 mg / (cubic cm). The molar mass of methane is 16.04 g / mol and molar mass of ethane is 30.07 g / mol. (i) Find the mass % of methane and ethane in the natural gas. (ii) Find the average density of the natural gas mixture in the reservoir at zero degree Celsius and one atmosphere, by assuming that the gases are ideal where final volume of the gas mixture is the sum of volume of the individual gases at constant temperature and pressure. (iii) Find the average density of the natural gas mixture in the reservoir at zero degree Celsius and one atmosphere, by assuming that the final mass of the gas mixture is the sum of mass of the individual gases. Assume the gases are ideal where mole % = volume % at constant pressure and temperature.
1 2654MASS TRANSFER - EXAMPLE 4.1 : A concentric, counter-current heat exchanger is used to cool lubricating oil. Water is used as the coolant. The mass flow rate of oil into the heat exchanger is 0.1 kg / s = FO. For oil, the inlet temperature TIO = 100 degree Celsius and the outlet temperature TOO = 55 degree Celsius. For water, the inlet temperature TIW = 35 degree Celsius and the outlet temperature TOW = 42 degree Celsius. What is the mass flow rate of water in kg / s, FW needed to maintain these operating conditions? Constant for heat capacity of oil is CO = 2131 J /(kg K) and for water is CW = 4178 J /(kg K). Use the equation (FO)(CO)(TIO ?TOO) = (FW)(CW)(TOW ?TIW).
1 2399Heat transfer: In a triple effect evaporator, the heat transfer for an evaporator is calculated as q = UA (TI - TF) where TI is the initial temperature, TF is the final temperature; U and A are constants. Given that heat transfer for the first evaporator : q(1) = UA (TI - TB); second evaporator : q(2) = UA (TB - TC); third evaporator : q(3) = UA (TC - TF) where q(x) is the heat transfer function, TB is the temperature of second inlet and TC is the temperature of third inlet, prove that the overall heat transfer Q = q(1) q(2) q(3) = UA (TI - TF).
1 2633how can i calibrate the temperatuture gauge used by temperature bath(dry block) i mean step by step procedure?
1628PROCESS CONTROL - EXAMPLE 6.2 : A stream with volumetric flow rate Q enters a cylindrical tank and a stream with volumetric flow rate q exits the tank. The fluid has a constant heat capacity and density. There is no temperature change or chemical reaction occurring in the tank. Develop a model for determining the height of the tank, h. Let V is the volume, A is the cross sectional area, r is the density, m is the mass, where V and A are for the tank, r and m are for the fluid. The rate of mass of fluid accumulation, dm / dt = (Q - q) r. Prove the model to be dh / dt = (Q - q) / A.
1 2222HEAT TRANSFER - EXAMPLE 5.3 : In a cylinder with a hollow, let a is outside radius and b is the inside radius. In a steady state temperature distribution with no heat generation, the differential equation is (d / dr) (r dT / dr) = 0 where r is for radius and T is for temperature. (a) Integrate the heat equation above into T(r) in term of r. (b) At r = a, T = c; at r = b, T = d. Find the heat equation of T(r) in term of r, a, b, c, d.
1 2369Our 8mw steam turbine (condensing cum extraction) exhaust steam temperature is high even after taken it in hogger why
1 3766THERMODYNAMIC - EXAMPLE 10.1 : The water is superheated steam at 440 degree Celsius and 17.32 megapascals. Estimate the enthalpy of the steam above. From the steam table for water at 440 degree Celsius, enthalpy of steam, h at 18 megapascals is 3103.7 kilojoules per kilogram and at 16 megapascal is 3062.8 kilojoules per kilogram. Assume that h = mP + c where P is pressure; m and c are constants at fixed temperature with small differences in P.
1 2198THERMODYNAMIC - EXAMPLE 10.3 : According to Raoult's law, the pressure when vapor is completely condensed, P = x(1) P(1) + x(2) P(2) ... + x(n) P(n) when x(1), x(2) ... x(n) are the mole fractions of component 1, 2 ... n and P(1), P(2) ... P(n) are the vapor pressures of component 1, 2 ... n. A vapor at 74 degree Celsius containing 70 mole % water and 30 mole % ethanol is to be completely condensed. At the temperature of 74 degree Celsius vapor pressure is 0.38 atm for water and 0.97 atm for ethanol. What is the minimum pressure the compressor must be operated?
1 2123CHEMICAL ENERGY BALANCE - EXAMPLE 11.1 : Please match the term A - E with the stated definition i - v. Terms : A. Yield. B. Selectivity. C. Relative saturation. D. Molal saturation. E. Absolute saturation. Definitions : i. (moles of desired product formed) / (moles that would have been formed if there were no side reactions and the limiting reactant has reacted completely); ii. (moles of desired product formed) / (moles of undesired product formed); iii. (relative humidity 40 % means partial pressure of water vapour equals 4 / 10 of the vapour pressure of water at the system temperature); iv. (moles of vapour) / (moles of vapour dry gas); v. (mass of vapour) / (mass of dry gas).
1 2134CHEMICAL ENERGY BALANCE - EXAMPLE 11.2 : Calculate the cooling duty, H required to condense and cool acetone from 100 degree Celsius to 25 degree Celsius at atmospheric pressure. The heat of vaporization for acetone at its normal boiling point is 30.2 kJ / mol. The boiling point of acetone at atmospheric pressure is 56 degree Celsius. The flowrate of acetone through the condenser is 100 mol / s = N. Value of sensible heat needed to increase the temperature of acetone in liquid form from 25 to 56 degree Celsius is 4.06 kJ / mol. Value of sensible heat needed to increase the temperature of acetone in vapor form from 56 to 100 degree Celsius is 3.82 kJ / mol. Unit of H is kJ / s.
1 2300
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I currently use 17-7 PH stainless which is hardened to condition CH after forming. raw matl is .1.75"X .12" X .008". Its main usage after hardening is silicon wafer retainer where it's contantly cycled up and down to putin and remove wafer after 40-60 sec process at 400C temp. At this high temperature this part seemed to deform after a a couple of hundred wafer which is what it was designed for in the first place. THere is a proposal to go to a different material to increase lifeline of this part. My question is..... can 321 SST be a plugin replacement. I know this has a higher temp rating but how about its forming characteristics, will it have spring properties, and wont become brittle after prolonged exposure to 400C.
Design a program which assigns values to the array temperature. The program should then display the array with appropriate column and row headings.
An ice-box is built of wood 1.75 cm thick, lined with cork 3 cm thick. If in the steady state the temperature of the inner surface of the cork is 0 ºC and that of the outer surface of wood is 12 ºC, what is the temperature of the wood-cork interface? The thermal conductivities of wood and cork are 0.2 W/m-K and 0.04 W/m-K respectively
What is the temperature PROFILE OF A FLUID W. R. T. Distance from a sphere to which it is IN CONTACT which is at constant temp.?
In which working principal temperature transmitter work.explain in detailed.
hii..i am doin a project called Forecaster..wat it does is it asks user to enter a zip code..then it establishes urlconnection with a weather website n fetches data n data is converted into graphical representation..but it doesnt show any output..i am not able it figure out the reason..can u plzzzz help me out..i am givin u code import java.io.*; import java.awt.*; import java.net.*; import java.awt.image.*; import java.awt.event.*; public class Forecast extends Frame { OkCancelDialog textDialog; BufferedImage image = null; public static void main(String[] args) { new Forecast(); } public Forecast() { String zip =""; File zipFile = new File("zip.txt"); String hiTemperature[] = new String[4]; String loTemperature[] = new String[4]; try { if(zipFile.exists()){ FileReader filereader = new FileReader("zip.txt"); BufferedReader bufferedreader = new BufferedReader(filereader); zip = bufferedreader.readLine(); } else { textDialog = new OkCancelDialog(this, "Enter your five-digit zip code", true); textDialog.setVisible(true); zip = textDialog.data.trim(); FileOutputStream fileoutputstream = new FileOutputStream("zip.txt"); fileoutputstream.write(zip.getBytes()); } int character; URL url = new URL ("http://www.srh.noaa.gov/zipcity.php?inputstring=" + zip); URLConnection urlconnection = url.openConnection(); InputStream in = urlconnection.getInputStream(); String input = ""; String hiSearch; String loSearch; String inchar; char[] cc = new char[1]; while ((character = in.read()) != -1) { char z = (char)character; cc[0] = z; inchar = new String(cc); input += inchar; } in.close(); if(input.indexOf("Hi ") >= 0){ hiSearch = "Hi "; } else{ hiSearch= "Hi: "; } int currentPosition = 0; for(int loopIndex = 0; loopIndex < 4; loopIndex++){ int location = input.indexOf(hiSearch, currentPosition); int end = input.indexOf("°", location); hiTemperature[loopIndex] = input.substring(location + hiSearch.length(), end); currentPosition = end + 1; } if(input.indexOf("Lo ") >= 0){ loSearch = "Lo "; } else{ loSearch= "Lo: "; } currentPosition = 0; for(int loopIndex = 0; loopIndex < 4; loopIndex++){ int location = input.indexOf(loSearch, currentPosition); int end = input.indexOf("°", location); loTemperature[loopIndex] = input.substring(location + loSearch.length(), end); currentPosition = end + 1; } boolean evening = false; if(input.indexOf(loSearch) < input.indexOf(hiSearch)){ evening = true; hiTemperature[3] = hiTemperature[2]; hiTemperature[2] = hiTemperature[1]; hiTemperature[1] = hiTemperature[0]; } image = new BufferedImage(225, 201, BufferedImage.TYPE_INT_RGB); Graphics2D g = image.createGraphics(); g.setColor(Color.white); g.fillRect(0, 0, 224, 201); g.setColor(Color.gray); for(int loopIndex = 0; loopIndex < 21; loopIndex++){ g.drawLine(25, loopIndex * 10, 224, loopIndex * 10); g.drawLine(loopIndex * 10 + 25, 0, loopIndex * 10 + 25, 199); } g.setColor(Color.blue); Font font = new Font("Courier", Font.PLAIN, 18); g.setFont(font); for(int loopIndex = 20; loopIndex < 200; loopIndex += 20){ g.drawString(String.valueOf(100 - loopIndex / 2), 0, loopIndex + 5); } g.setColor(Color.red); if(!evening){ g.drawOval(65 - 4, 200 - (Integer.parseInt( hiTemperature[0]) * 2) - 4, 8, 8); } g.drawOval(105 - 4, 200 - (Integer.parseInt( hiTemperature[1]) * 2) - 4, 8, 8); g.drawOval(145 - 4, 200 - (Integer.parseInt( hiTemperature[2]) * 2) - 4, 8, 8); g.drawOval(185 - 4, 200 - (Integer.parseInt( hiTemperature[3]) * 2) - 4, 8, 8); if(!evening){ g.drawLine(65, 200 - (Integer.parseInt( hiTemperature[0]) * 2), 105, 200 - (Integer.parseInt(hiTemperature[1]) * 2)); } g.drawLine(105, 200 - (Integer.parseInt(hiTemperature[1]) * 2), 145, 200 - (Integer.parseInt(hiTemperature[2]) * 2)); g.drawLine(145, 200 - (Integer.parseInt(hiTemperature[2]) * 2), 185, 200 - (Integer.parseInt(hiTemperature[3]) * 2)); g.setColor(Color.blue); g.drawOval(65 - 4, 200 - (Integer.parseInt( loTemperature[0]) * 2) - 4, 8, 8); g.drawOval(105 - 4, 200 - (Integer.parseInt( loTemperature[1]) * 2) - 4, 8, 8); g.drawOval(145 - 4, 200 - (Integer.parseInt( loTemperature[2]) * 2) - 4, 8, 8); g.drawOval(185 - 4, 200 - (Integer.parseInt( loTemperature[3]) * 2) - 4, 8, 8); g.drawLine(65, 200 - (Integer.parseInt(loTemperature[0]) * 2), 105, 200 - (Integer.parseInt(loTemperature[1]) * 2)); g.drawLine(105, 200 - (Integer.parseInt(loTemperature[1]) * 2), 145, 200 - (Integer.parseInt(loTemperature[2]) * 2)); g.drawLine(145, 200 - (Integer.parseInt(loTemperature[2]) * 2), 185, 200 - (Integer.parseInt(loTemperature[3]) * 2)); g.setColor(Color.white); g.fillRect(55, 160, 140, 30); g.setColor(Color.blue); g.drawRect(55, 160, 140, 30); font = new Font("Courier", Font.PLAIN, 12); g.setFont(font); g.drawString("Four-Day Forecast", 65, 172); font = new Font("Courier", Font.PLAIN, 9); g.setFont(font); g.drawString("Source: Nat. Weather Srvce.", 58, 185); setTitle("The Forecaster"); setResizable(false); setSize(250, 240); setVisible(true); this.addWindowListener(new WindowAdapter(){ public void windowClosing( WindowEvent e){ System.exit(0); } } ); } catch (Exception e) { System.out.println(e.getMessage()); } } public void paint(Graphics g) { if(image != null){ g.drawImage(image, 10, 30, this); } } } class OkCancelDialog extends Dialog implements ActionListener { Button ok, cancel; TextField text; public String data; OkCancelDialog(Frame hostFrame, String title, boolean dModal) { super(hostFrame, title, dModal); setSize(280, 100); setLayout(new FlowLayout()); text = new TextField(30); add(text); ok = new Button("OK"); add(ok); ok.addActionListener((ActionListener)this); cancel = new Button("Cancel"); add(cancel); cancel.addActionListener(this); data = new String(""); } public void actionPerformed(ActionEvent event) { if(event.getSource() == ok){ data = text.getText(); } else { data = ""; } setVisible(false); } }
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What is the maximum cylinder head temperature of a 1200 KW, 12 cylinders DG set