class CTest { public: void someMethod() { int nCount = 0;

class CTest
{
public:
void someMethod()
{
int nCount = 0;
cout << "This is some method --> " << nCount;
}
};

int main()
{
CTest *pctest;
pctest->someMethod();
return 0;
}

It will executes the someMethod() and displays the value
too. how is it possible with our creating memory for the
class . i think iam not creating object for the class.
Thanks in Advance...
Prakash

Question Posted / prakashdasari

1 Answers
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class CTest { public: void someMethod() { int nCount = 0; cout << "..

Answer / Hirawan Lal

In this code, you are defining a class named CTest and its method someMethod. However, to execute the someMethod() and display its output, you need to create an object of the class CTest. This can be done using the 'new' keyword followed by the class name. For example: CTest pctest(new CTest()); pctest.someMethod();

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