If a bear eats 65 pounds in fish every day EXCEPT every 6th
day which it only eats 45 pounds of fish.
If the bear continues this, how many pounds of fish will it
eat in 200 days?
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Answer / guest
The bear will eat 12,340 pounds of fish in 200 days.
It is given that on every 6th day beareats 45 pounds of fish
i.e. on day number 6, 12, 18, 24, .... 192, 198 the bear
eats 45 pounds of fish.
Total number of 6th days = 200/6 = 33 (the bear eats 45 pounds)
Hence, the normal days are = 200 - 33 = 167 (the bear eats
65 pounds)
Thus, in 200 days, the bear will eat
= (167) * (65) + (33) * (45)
= 10855 + 1485
= 12,340 pounds
| Is This Answer Correct ? | 28 Yes | 2 No |
Answer / anjana r
So,
1.lets first calculate the amt for
65 pounds in 200 days= 65*200=13000
2.Now we have see how total numb of 6th
days in 200 days= 200/6=33
3.Now on the 6th days(33 days) only 45 pound
was eaten.Now that we have calculated for all 25 days
in first step,lets is take away the extra pounds that were
calculed= 65-45 =20 pounds extra was calculated for 33 dys
Therefore,
33* 20=660 pounds
13000-660=12340 pounds were consumed by the bear for 200 days.
| Is This Answer Correct ? | 2 Yes | 0 No |
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